\( 0 = 20^2 - 2 \times 9.8 \times h \)
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- A ball is thrown upward with an initial velocity of 20 m/s. Ignoring air resistance, how high does it go? (Use \( g = 9.8 \, \text{m/s}^2 \))
- The maximum height is reached when the velocity is 0.
- Using \( v^2 = u^2 - 2gh \), where \( v = 0 \), \( u = 20 \), and \( g = 9.8 \):
- \( 400 = 19.6h \)
- \( h = \frac{400}{19.6} \approx 20.41 \) meters.
- #### 20.41
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